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In Physics / High School | 2014-10-09

Suppose an astronaut drops a feather from a height of 1.2 meters above the surface of the moon. If the free fall acceleration on the moon is [tex]1.62 \, \text{m/s}^2[/tex] downward, how long does it take for the feather to hit the moon's surface?

Asked by Onuoraawesome

Answer (2)

1.62/1.2 = 1.35
It takes 1.35 seconds to fall

Answered by i3clynn | 2024-06-10

A feather dropped from a height of 1.2 meters on the moon takes about 1.22 seconds to reach the surface. This is calculated using the formula for distance under uniform acceleration due to gravity. The moon's gravity is 1.62 m/s², allowing us to derive the time of fall.
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Answered by Anonymous | 2024-12-26

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