find the zeros of the function by rewriting the function in intercept form

[y=3x^2+2x\ y=x(3x+2)\ y=x(x+\frac{2}{3})\ x=0 \vee x=-\frac{2}{3}\\ f(x)=5x^2-25x+30\ f(x)=5(x^2-5x+6)\ f(x)=5(x^2-2x-3x+6)\ f(x)=5(x(x-2)-3(x-2))\ f(x)=5(x-3)(x-2)\ x=3 \vee x=2
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Answered by konrad509 | 2024-06-10

To find the zeros of the function, we can rewrite it in intercept form. By factoring the function and setting the factors equal to zero, we determine the zeros, which in this example are x = 0 and x = -2/3. This method illustrates how to find the points where the graph intersects the x-axis.
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Answered by konrad509 | 2024-12-26