Raphael paid $636 for a camera during a 20% off sale. What was the camera's regular price?

The question regards reverse-percentages. This requires you to realise what percentage of the original amount the sale price represents. If the original price is 100% and you have lost 20%, the sale price is 80% of the original.
To get from the original price to the sale price, you would multiply by 80%, or its respective decimal multiplier of 0.8. Therefore it follows that to go the other way (to go from the sale price to the original price), you need to divide by 0.8:
$636 / 0.8 = $795
In case you weren't sure how to find the decimal multiplier, all you have to do is divide the percentage by 100. So for a percentage of 156%, the decimal multiplier is 156 / 100 = 1.56
I hope this helps

Answered by DavidOrrell | 2024-06-10

present price = original price x multiplier original price = present price/multiplier multiplier = (100-20)/100 = 0.8 original price = 636/0.8 = $795

Answered by RhysH | 2024-06-10

The regular price of the camera was $795, calculated by recognizing that the sale price of $636 is 80% of the original price. Dividing $636 by 0.8 gives the original price. Therefore, Raphael's camera originally cost $795 before the 20% discount.
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Answered by DavidOrrell | 2024-12-26