If \(A + B = 76\) and \(A - B = 38\), what is \(\frac{A}{B}\)?

A+B=76 A-B=38
A=38+B
Substitute into other 38+B+B=76 2b=38 b=19 A+19=76 A=38 B=19

Answered by henryw90 | 2024-06-10

\ \ A=38+B\\\\ 38+B+B=76\\ 38+2B=76\ \ | subtract\ 38\\2B=38\ \ \ | divide\ by\ 2\\ B=19\\A=57\\\\ \frac{A}{B}=\frac{57}{19}=3"> A + B = 76 A − B = 38 − − − > A = 38 + B 38 + B + B = 76 38 + 2 B = 76 ∣ s u b t r a c t 38 2 B = 38 ∣ d i v i d e b y 2 B = 19 A = 57 B A ​ = 19 57 ​ = 3

Answered by luana | 2024-06-10

We solved the equations A + B = 76 and A − B = 38 to find A = 57 and B = 19 . The ratio B A ​ is then calculated as 19 57 ​ ≈ 3 .
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Answered by Anonymous | 2024-10-02