one way you could do it is by using the roster or list meathod which is normaly long and tedius. RBG RGB GRB GBR BRG BGR so six possibilities
the easier way is to use permutations also nicknamed the slot meathod by my teacher so in the first slot there are 3 choices in the 2nd slot there are 2 choices since one was already taken up by the 1st slot 3rd slot 1 choice because 1 was taken by slot 2 so 3 times 2 times 1=6 or six posssiblities
So if we look at our roster/list, 2 out of 6 times or 2/6 or 1/3 of the permutations the Green car was first
There are six different orders for parking the red, blue, and green cars. The probability that the green car is first is 3 1 . Thus, we can conclude that the green car has a 1 out of 3 chance of being the first car parked.
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