y=10x+20 y=10×5y+20 y=50y+20 -20=50y-y -20=49y y=-20/49
x = -2.04
y = - 0.408 ;
To solve the system of equations X = 5 y and y = 10 x + 20 , we substitute x from the first equation into the second. This leads to solving for y , which we substitute back to find x . The solutions are approximately x ≈ − 2.04 and y ≈ − 0.408 .
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