The length of Marshall's poster is 2 times its width. If the perimeter is 72 inches, what is the area of the poster?

X= width 2x= length 2x+4x=72 6x=72 X=12 2(12)x(12)=24x12 The answer is 288 sq. in.

Answered by jschoettlejam | 2024-06-10

x − w i d t h 2 x − l e n g t h 2 x + 2 ⋅ 2 x = 72 2 x + 4 x = 72 6 x = 72 ∣ : 6 x = 12 2 x = 2 ⋅ 12 = 24 A re a = 24 ⋅ 12 = 288 i n 2

Answered by luana | 2024-06-10

The area of Marshall's poster is calculated by first finding the width as 12 inches and the length as 24 inches. Then, using the area formula for a rectangle, we find the area to be 288 square inches. Therefore, the final area is 288 square inches.
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Answered by jschoettlejam | 2024-12-26