The initial proposed absolute value inequality |x + 1| < 4 was incorrect as it did not include the solutions 3 and -5. The corrected inequality is |x + 1| ≤ 4, which successfully includes both 3 and -5 as solutions. ;
An absolute value inequality that has 3 and -5 as solutions is ∣ x + 1∣ ≤ 4 . This inequality is derived by finding the midpoint and distance between the two solutions. Testing both solutions confirms they satisfy the inequality.
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