Use the substitution method to solve the system of equations:

1. \( Y = 6x \)
2. \( Y = 5x + 7 \)

\left\{\begin{array}{ccc}y=6x\\y=5x+7\end{array}\right\\\\subtitute\ y=6x\ to\ the\ second\ equation\\\\6x=5x+7\ \ \ \ \ |subtract\ 5x\ fron\ both\ sides\\\boxed{x=7}\\\\subtitute\ value\ of \x=7\ to\ the\ equation\ y=6x:\\\\y=6\cdot7\\\boxed{y=42}\\\\Answer:\\ \left\{\begin{array}{ccc}x=7\\y=42\end{array}\right

Answered by Anonymous | 2024-06-10

{ y = 5 x + 7 y = 6 x ​ S u b s t i t u t i o n m e t h o d 6 x = 5 x + 7 ∣ s u b t r a c t 5 x x = 7 y = 6 ∗ 7 = 42

Answered by luana | 2024-06-10

Using the substitution method, we substituted Y = 6 x into Y = 5 x + 7 and solved for x , finding x = 7 . Then, substituting back, we found Y = 42 . The solution to the system of equations is ( 7 , 42 ) .
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Answered by Anonymous | 2024-12-26