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In Physics / High School | 2014-11-20

A person runs off a cliff into a lake below. If the person leaves the cliff with a horizontal velocity of 4 m/s, how far away from the cliff does he land if the cliff is 17 m high?

Asked by Nostalgic

Answer (2)

When you drop an object from a height of 17m, it hits the ground 1.86 seconds later, with a speed of 18.25 m/s.
That's the same time it takes our daredevil to hit the water. During the 1.86 seconds that he's falling and yelling, he's traveling 4m/s horizontally, and lands 7.45 meters from the bottom of the cliff.
Let's hope the water begins closer to the cliff than that.

Answered by AL2006 | 2024-06-10

The person will land approximately 6.96 meters away from the cliff after jumping off horizontally at a velocity of 4 m/s and falling from a height of 17 meters. The time to fall is determined using the free fall equation, and then the horizontal distance is calculated using the time in the air. This exemplifies the concept of projectile motion, combining vertical and horizontal components.
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Answered by AL2006 | 2024-11-25