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In Physics / High School | 2014-11-22

A 90-kg tight end moving at 9.0 m/s encounters a 400 N•s impulse. Determine the velocity change of the tight end.

Asked by isiranwar

Answer (3)

Δp=mΔv 400 N.s = (90kg) (vf-9m/s) 400 = 90 vf - 810 400 + 810 = 90 vf 1210 = 90vf vf= 13.4 m/s

Answered by Anonymous | 2024-06-10

Answer: The change velocity of the tight end is 4.44 m/s ;

Answered by IlaMends | 2024-06-24

The change in velocity of the 90-kg tight end, after receiving a 400 N•s impulse, is approximately 4.44 m/s. This was calculated using the impulse-momentum theorem. The final velocity after the impulse is about 13.44 m/s.
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Answered by IlaMends | 2024-10-13

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