How do you calculate moments with 3 separate weights of different amounts at different points?

Weights and distances:

- 200 N located at the left end
- 100 N located 2 meters from the left end
- 300 N located at the right end

Distances between weights:

- 2 meters between the 200 N weight and the 100 N weight
- 1 meter between the 100 N weight and the right end

Diagram representation:

200 N 100 N 300 N
-------------------------------------------------------------------------------------
<---------------2M----------------> /_\ <---------------2M-------------->

What would the moments be?

I don't completely understand your drawing, although I can see that you certainly did put a lot of effort into making it. But calculating the moment is easy, and we can get along without the drawing.
Each separate weight has a 'moment'. The moment of each weight is:
** (the weight of it)** x (its distance from the pivot/fulcrum) .
That's all there is to a 'moment'.
The lever (or the see-saw) is balanced when (the sum of all the moments on one side) is equal to (the sum of the moments on the other side).
That's why when you're on the see-saw with a little kid, the little kid has to sit farther away from the pivot than you do. The kid has less weight than you do, so he needs more distance in order for his moment to be equal to yours.

Answered by AL2006 | 2024-06-10

To calculate moments, multiply each force by its distance from the pivot and add them considering direction to find the net moment. Use the principle of moments for equilibrium. ;

Answered by JoaquinRafael | 2024-06-18

To calculate moments with weights, use the formula: Moment = Force x Distance from the pivot. For a 200 N weight at the left end, 100 N at 2 m, and 300 N at the right end, the total moment is 1100 N·m. Always select a pivot point and measure distances from it to find individual moments for each weight.
;

Answered by AL2006 | 2024-12-26