Two bowling balls each have a mass of 6.9 kg. They are located next to each other with their centers 21.8 cm apart.
What gravitational force do they exert on each other?
Answer (3)
We can start with Newton's Law of Universal Gravitation, which is F g r a v = ( G . m 1 . m 2 ) / d 2 Otherwise known as... The force due to gravity between two objects is equal to G ( a universal constant G = 6.673 x 10-11 N m2/kg 2) times the mass of the first object (kg) times the mass of the second object (kg) all divided by the distance between the two objects squared.
We can thus plug in the given values to receive the answer... F g r a v = ( 6.673 x 1 0 − 11 . ( 6.9 ) 2 ) / ( 0.218 ) 2 I converted the 21.8cm into 0.218m, for the equation calls for meters.
I hope this helps!
P.S. I'm currently enrolled in IB Physics, so if you have any more questions, feel free to contact me for help.
The gravitational force between two 6.9 kg bowling balls, which are 21.8 cm apart, is approximately 1.99 x 10^-9 Newtons , showing the relative weakness of gravitational forces at an everyday scale. ;
The gravitational force between the two bowling balls is calculated using Newton's Law of Universal Gravitation. Substituting the masses and distance into the formula gives a gravitational force of approximately 6.68 × 1 0 − 8 N . This demonstrates the very small gravitational attraction between objects of ordinary mass and distance.
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