x − w i d t h 2 x − l e n g t h 2 l e n g t h + 2 w i d t h = p er im e t er 240 = 2 x + 4 x 240 = 6 x ∣ d i v i d e b y 6 x = 40 D im e n s i o n s : w i d t h = 40 y a r d s l e n g t h = 80 y a r d s .
The **length **of the rectangular athletic field is 80 yards and the width is 40 yards.
What are the area and perimeter of a rectangle?
We know the perimeter of any 2D figure is the **sum **of the lengths of all the sides except the circle and the area of a rectangle is the product of its length and width.
We know, Perimeter of a rectangle is 2(length + width) .
From the given information, A rectangular athletic field is twice as long as it is wide.
Let, The width be ' x ' hence the length be ' 2x '.
Therefore,
2(x + 2x) = 240.
2(3x) = 240.
3x = 120.
x = 40.
So, The width is 40 yards and the **length **is 80 yards.
learn more about **rectangles **here :
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The rectangular athletic field has a width of 40 yards and a length of 80 yards. This is determined by setting up equations based on the relationship between the length and width and the given perimeter of 240 yards. By solving these equations, we find the dimensions of the field.
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