A boy is 24 years younger than his father. In 2 years, the sum of their ages will be 40. Find the present ages of the father and son.

Let the age of the boy be x. Therefore the age of the father = x + 24. (The boy is 24 years younger implies that his father is older by 24 years).
In 2 years time: The boy will be = (x +2). The father will be (x +24 +2) = (x + 26).
Sum of their ages = 40. Therefore (x+2) + (x + 26) = 40. x + x + 2 + 26 = 40 2x + 28 = 40 2x = 40 -28 2x = 12. x = 12/2 = 6. x =6. Present ages = x , x +24. = 6, (6 +24) = 6, 30. Boy = 6 years old. Father = 30 years old. Cheers.

Answered by olemakpadu | 2024-06-10

ooh fun
x=boy y=father x+24=y (x+2)+(y+2)=40 subsitute x+24=y into equation x+2+x+24+2=40 add like terms 2x+28=40 subtract 28 from both sides 2x=40 divide both sides by 2 x=son now=20 father=son+24 father=20+24=44
father=44 son=20

Answered by apologiabiology | 2024-06-10

The boy is currently 6 years old, and his father is 30 years old. In two years, their ages will add up to 40. This is consistent with the given conditions of the problem.
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Answered by olemakpadu | 2024-10-09