The energy required to lift two skiers to the top of the mountain is 240,000 J.
The electric motor has an efficiency of 40%.
Calculate the energy wasted in the motor.
Answer (3)
The motor is 40% efficient. The energy required is 240 000 J. This can not be negotiated, it must be supplied by the motor. But the motor would supply more than that amount, to be able to do a work of 240 000 J, because it is not 100% efficient.
Efficiency = Work Output / Work Input. , E= 40% = 0.40
The required work output is the do the 240 000 J of work.
0.40 = 240 000 / Wi Wi = 240 000 / 0.40 = 600 000 J.
That is the input energy into the motor. So amount wasted = 600 000 - 240 000 = 360 000 J. Usually as heat. That's it. Cheers.
The wasted energy in the motor is calculated by finding the difference between the total energy input and the useful energy output. Given the motor's efficiency of 40%, the energy wasted is found to be 360,000 Joules.
To calculate the energy wasted in the electric motor, we must first understand that the motor's efficiency is the ratio of the useful energy output to the total energy input. In this case, the efficiency is given as 40%, or 0.40. The useful energy output required to lift the skiers is 240,000 J. Since this is 40% of the energy input, we can calculate the total energy input by dividing the useful energy by the efficiency:
Total Energy Input = Useful Energy / Efficiency
Now, we calculate the total energy input:
Total Energy Input = 240,000 J / 0.40 = 600,000 J
The energy wasted is the difference between the total energy input and the useful energy output:
Energy Wasted = Total Energy Input - Useful Energy Output
Energy Wasted = 600,000 J - 240,000 J = 360,000 J
Therefore, the energy wasted in the motor is 360,000 J.
The energy wasted in the motor is calculated to be 360,000 J. This is determined by using the motor's efficiency of 40% and the energy required to lift the skiers, which is 240,000 J. The total energy input required by the motor is 600,000 J, leading to the wasted energy calculation.
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