A liquid with a specific heat of 1,900 J/kg·°C has 4,750 joules of heat energy added to it. If the temperature increases from 20°C to 30°C, what is the mass of the liquid?
Answer (2)
Q=mcΔT
Q=heat energy = 4750J m=mass = ? c= specific heat capacity = 1900J/(K·kg) ΔT=change in heat = 30-20=10
m = c ( d T ) Q = 0.025kg=25g
The mass of the liquid is approximately 0.25 kg (or 250 grams) after calculating the heat transfer using the specific heat formula. We used the given values of heat energy, specific heat capacity, and the change in temperature. This method allows us to determine the mass of the liquid efficiently.
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