An object is thrown off a cliff with a horizontal speed of 10 m/s. After 3 seconds, the object hits the ground.

Find the height of the cliff and the total horizontal distance traveled by the object.

a. What do you know?

b. What do you need to solve for?

c. What equation(s) will you use?

d. What is the solution to this problem?

An object is thrown off a cliff with a horizontal speed of 10 m/sec. After 3 seconds the object hits the ground. The height of the cliff and the total horizontal distance traveled by the object (S)= 30m.
What is velocity?
Velocity is a physical term that means a particle change its distance in a given** time**. That called the velocity. It can be measured in m/s or cm/s.
How can we calculate the height?
To calculate the height we are using the formula here is,
S=vt
Here we are given,
v= The velocity of the object.= 10 m/s.
t= The** time **of the falling. = 3 s.
We have to calculate the** height **of the cliff = S
Now we put the values in the above equation, we get
S=vt
Or, S= 10×3
Or, S= 30
From the above calculation we can say that, The height of the cliff and the total horizontal distance traveled by the object (S)= 30m.
Learn more about velocity:
https://brainly.com/question/25749514
#SPJ2

Answered by Michaelcann | 2024-06-16

The height of the cliff is approximately 44 meters, and the total horizontal distance traveled by the object is 30 meters. This was calculated using the equations of motion for vertical and horizontal distances. ;

Answered by JaymaMays | 2024-06-18

The height of the cliff is approximately 44.15 m, and the total horizontal distance traveled by the object is 30 m.
;

Answered by Michaelcann | 2024-10-09