A helicopter's speed increases from 25 m/sec to 60 m/sec in 5 seconds. What is the acceleration of this helicopter?

It increases by 60-25=35 m/s. Divide that by the time (5 seconds) to get 7 m / s 2

Answered by Anonymous | 2024-06-10

Acceleration = Vf - Vi / t, where Vf is the final velocity, Vi is the initial velocity, and t is the time. It is given that the helicopter’s speed increases from 25 m/s to 60 m/s in 5 s, so Vf = 60 m/s, Vi = 25 m/s, and t = 5. When putting this into the equation you get 60 - 25 / 5 which can simplify to 35 /5 also known as 7 m/s^2.

Answered by abigaeldalpaca | 2024-06-12

The helicopter's acceleration, calculated as the change in velocity divided by the time taken for that change, is 7 m/s². This indicates the speed of the helicopter increases by 7 meters per second for every second it is accelerating. Thus, acceleration is a measure of how quickly the helicopter speeds up.
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Answered by Anonymous | 2024-12-23