a) 120 vibrations per minute b)d) 2 Hz (vibrations per second) c) The period is half of the second.
Explanation :
It is given that an oscillator makes 360 oscillations in 3 minutes.
(a) Using unitary method :
No. of vibrations in one minute is, n = 3 360 = 120
So, no of vibrations in one minute is 120.
**(b) Similarly, **
3 minutes = 180 seconds
No of vibrations in one second is 180 360 = 2
So, the no of vibrations in one second is 2.
(c) Time period of the wave is given by :
T = 2 s − 1 1
T = 0.5 s
The time period of the wave is 0.5 s
(d) The no of vibation per second is called as its frequency.
ν = T 1
ν = 2 Hz
Hence, this is the required solution.
The oscillator makes 120 vibrations in one minute and 2 vibrations in one second. Its period is 0.5 seconds, and the frequency is 2 hertz (Hz).
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