What is the volume of a 3.00 M (mol/L) solution made with 122 g of LiF?
Answer (3)
** 1.567** L is the volume of a 3.00M (mol/L) solution made with 122g of LiF .
Define molarity of a solution.
**Molarity **(M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. **Molarity **is also known as the molar **concentration **of a solution.
M o l a l i t y = S o l v e n t in k g M o l es so l u t e
Firstly calculate the moles of LiF.
Moles = m o l a r ma ss ma ss
Moles = 25.94 122 g . ( 25.94 is the molar mass of LiF)
Moles = 4.703
Now find the volume:
M o l a r i t y = V o l u m e o f so l u t i o n in l i t re M o l es so l u t e
3.00 M = V o l u m e o f so l u t i o n in l i t re 4.703
V = 1.567 L
Hence,** 1.567 L ** is the volume of a 3.00M (mol/L) solution made with 122g of LiF.
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The volume of a 3.00M solution made with 122g of LiF is calculated by first determining the number of moles of LiF and then dividing by the molarity. The volume is approximately 1.57 liters.
To find the volume, we need to calculate the number of moles of LiF and then use the molarity to find the volume. The molarity (M) is a measure of concentration indicating moles of solute per liter of solution.
To calculate the number of moles of LiF, we use the formula: moles = mass (g) / molar mass (g/mol). Lithium fluoride (LiF) has a molar mass of about 25.94 g/mol. Therefore, for 122g we have:
moles of LiF = 122 g / 25.94 g/mol ≈ 4.7 moles.
Given a 3.00M solution, to find the volume, we use the formula: Volume (L) = moles of solute / molarity (mol/L). Thus, the volume of the solution is:
Volume = 4.7 moles / 3.00 M ≈ 1.57 L. The volume of the 3.00M solution made with 122g of LiF is approximately 1.57 liters.
The volume of a 3.00 M solution made with 122 g of LiF is approximately 1.57 L. This is calculated by first finding the moles of LiF, then using the molarity equation to find the volume. Molar mass and the number of moles are critical for this calculation.
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