A store mixes red fescue worth $12 per pound and chewings fescue worth $16 per pound. The mixture is to sell for $15 per pound. How much of each should be used to make a 552-pound mixture?

x - how much of red fescue is needed for one pound of mixture y - how much of chewings fescue is needed for one pound of mixture x 12+ y 16 = 15 x + y = 1 so, x=1-y putting it into first line: (1-y) 12 + y 16 = 15 12 - 12 y + 16 y = 15 4 y = 3 y=3/4 so, x= 1-3/4; x=1/4 So to produce 552 pounds of mixture we need.. To produce 1 pound of mixture we need: 3/4 pound of red fescue and 1/4 pound of chewing fescue so to produce 552 pounds of miture we need: 552 3/4 - red fescue, which is 414 pounds needed and 552/4 - chewings fescue, which is 138 pounds needed

Answered by FileT | 2024-06-10

e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)

e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6 ;

Answered by 26sparedes91 | 2024-06-12

To create a 552-pound mixture, 414 pounds of red fescue and 138 pounds of chewings fescue should be used. This combination will maintain the desired average price of $15 per pound. The calculations involved setting up a system of equations based on weight and cost.
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Answered by FileT | 2024-12-23