xy=520 & y=x+6 xy = x*(x+6) = x^2 + 6x x^2+6x-520 = 0
=> x = {-26, 20}
When x = -26, y = -20 x = 20, y = 26
it was the answer the above comment ;
The two numbers are 20 and 26, with 26 being 6 more than 20. Their product is 520. Thus, the solution satisfies the conditions of the problem.
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