Write the balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI.
Answer (3)
P b ( Cl O 3 ) 2 ( a q ) + 2 N a I ( a q ) = P b I 2 ( s ) + 2 N a Cl O 3 ( a q )
The balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is as below
**Pb(ClO3)2(aq) + 2NaI(aq) → PbI2(s) + 2 NaClO3(aq)
**Explanation
from the equation above 1mole of lead(ii) chlorate Pb(ClO3)2 react with 2 moles of sodium iodide to form 1 moles of lead(ii) iodide( PbI2) and 2 moles of sodium chlorate NaClO3.
The balanced chemical equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is Pb(ClO3)2 (aq) + 2NaI (aq) → PbI2 (s) + 2NaClO3 (aq). This indicates that one mole of lead(II) perchlorate reacts with two moles of sodium iodide to form one mole of lead(II) iodide and two moles of sodium perchlorate. The equation is balanced with respect to all involved elements.
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