What mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide?

Note: Ensure to use stoichiometric calculations for the reaction.

CI2 + 2Nal ---> 2NalCI + I2 Nal = 149.9 g/mol. NaCI = 58.5 g/mol 2 mol Nal makes 2 mol NaCI 0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI 00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)

Answered by UFGators | 2024-06-24

Approximately 0.113 grams of sodium chloride is produced when 0.29 grams of sodium iodide reacts with chlorine gas. This was calculated using stoichiometric principles based on the balanced chemical reaction. By determining the moles of sodium iodide and applying the mole ratio, we converted the result back to grams.
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Answered by UFGators | 2024-09-30