A squirrel sitting on the ground starts to run with an acceleration of [tex]5.1 \, \text{m/s}^2[/tex]. How fast is the squirrel going after 0.25 seconds?

A. 20.4 m/s
B. 1.28 m/s
C. 0.49 m/s
D. 3.1 m/s

initial speed = 0 final speed = v acceleration = 5.1 time taken = 0.25 v=u+at v=1.28 m /s

Answered by Shashank | 2024-06-10

The velocity of the squirrel after 0.25 seconds of accelerating at 5.1 m/s² is approximately 1.28 m/s. This is calculated using the formula for final velocity, considering the initial velocity is 0 m/s. Hence, the correct option is B. 1.28 m/s .
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Answered by Shashank | 2024-09-30