You're conducting a physics experiment on another planet. You drop a rock from a height of 2.3 m and it hits the ground 1.1 seconds later. What is the acceleration due to gravity on this planet?

A. 4.2 m/s\(^2\)
B. 3.8 m/s\(^2\)
C. 2.4 m/s\(^2\)
D. 9.8 m/s\(^2\)

You get 2.3 = 1.21 ∗ 2 a ​ or 4.6 = 1.21 a or a = 3.802 (B)

Answered by Anonymous | 2024-06-10

** **Acceleration due to gravity on this planet will be 3.802 m / s^2
What are equations of motion?
**Equation of motion **are defined as equations that describe the behavior of a physical system in terms of its motion as a function of time
Using **equation of motion **
u=0
s= 2.3 m
t = 1.1 sec
to find = g (acceleration due to gravity on this planet)
s = u t + 1/2 (a ) (t ^(2))
s = 1/2 (g) (t^2)
2.3 = 1/2 (g) (1.1^2)
g = 2 * 2.3 /(1.1)^2
g = 4.6 /1.21= 3.802
correct answer is b) g = 3.802 m / s^2
Learn more about equation of motion
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Answered by AnkitaSi | 2024-06-16

The acceleration due to gravity on the other planet is calculated to be approximately 3.8 m/s². Thus, the correct answer from the given choices is B. 3.8 m/s².
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Answered by AnkitaSi | 2024-09-20