A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is the volume of the balloon at 46°C?
Answer (3)
This problem requires a certain equation. That equation is V1/T1=V2/T2, where V1 is your initial volume (535 mL in this case), T1 is your initial temperature in Kelvin(23 degrees C = 296 K), V2 is your final volume (unknown), and T2 is your final temperature (46 degrees C = 319 K). By plugging in these values, the equation looks like this: 535/296=V2/319. Now multiply both sides of the equation by 319, and your final answer is V2= 576.6 mL
The volume of balloon at 46 ∘ C is 576.5 mL . ;
Using Charles's Law, the final volume of the balloon at 46°C is found to be approximately 577.3 mL. This is calculated with the formula T 1 V 1 = T 2 V 2 , where the temperatures are converted to Kelvin. Therefore, when the temperature increases, the volume of the gas also increases accordingly.
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