An object is thrown horizontally from the open window of a building. If the initial speed of the object is 20 m/s and it hits the ground 2.0 s later, from what height was it thrown? (Neglect air resistance and assume the ground is level.)

The object was thrown from a height of 19.6 meters. By plugging in the time the object was in the air (2.0 s) into the free fall formula, we can find the vertical displacement.
Finding the height from which an object was thrown horizontally
To find out from what height the object was thrown, we need to use the formula for vertical displacement in free fall, which is y = 0.5 * g * t^2, where g is the acceleration due to gravity (9.8 m/s2) and t is the time the object spent in the air.
Plugging in the given values:

time (t) = 2.0 s
acceleration due to gravity (g) = 9.8 m/s2

We calculate the height (y) as follows:
y = 0.5 * 9.8 m/s2 * (2.0 s)2
y = 0.5 * 9.8 m/s2 * 4.0 s2
y = 19.6 m
So, the object was thrown from a height of 19.6 meters above the ground.

Answered by YogitaS | 2024-06-24

The object was thrown from a height of 19.6 meters. This was calculated using the free fall equation considering the time of fall as 2 seconds. The horizontal speed does not affect the height calculation in this scenario.
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Answered by YogitaS | 2024-09-27