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In Physics / Middle School | 2014-04-23

A dart is thrown horizontally with an initial speed of 10 m/s toward point P, the bull's-eye on a dartboard. It hits at point Q on the rim, vertically below P, 0.19 s later.

(a) What is the vertical distance between points P and Q?
(b) How far away from the dartboard is the dart released?

Asked by Hodor

Answer (2)

D=s(t) so it would be d=10(.19) d=.19 FOR BITH SNDWERS

Answered by mtresley | 2024-06-10

The vertical distance between points P and Q is approximately 0.177 m (or 17.7 cm). The dart was released approximately 1.9 m away from the dartboard. Both results are obtained using the formulas for motion under gravity and horizontal motion.
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Answered by Anonymous | 2024-10-01

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