Mr. Knote, a piano tuner, taps his 440 Hz tuning fork with a mallet. What is the period of the vibrating fork?

The question asks to determine the period of a vibrating tuning fork with a frequency of 440 Hz. The period of a wave is the inverse of the frequency. Given that the frequency of the tuning fork is 440 Hz, we can calculate the period (T) using the formula:
T = 1 / f
Where T is the period and f is the frequency. Substituting in the given frequency:
T = 1 / 440 Hz
= 0.00227 seconds (rounded to five decimal places)
Therefore, the period of the vibrating 440 Hz tuning fork is approximately 0.00227 seconds.

Answered by ArmyArcherd | 2024-06-24

By using the relation between** period **and frequency , we conclude that the **period of the fork is **0.0023 seconds.
What is the period of the vibrating fork?
We know that the relation between **period **and **frequency **is:
T = 1/f
where T is the **period **and f is the frequency .
In this case, we know that the **frequency **of the fork is 440 Hz, where:
1 Hz = 1/s
Then the **period **of the fork will be:
T = 1/(440 Hz) = (1/440) s = 0.0023 s
Meaning that each complete **vibration **of the fork takes 0.0023 seconds.
If you want to learn more about waves , you can read:
https://brainly.com/question/15531840

Answered by facundo3141592 | 2024-06-25

The period of the vibrating fork is approximately 0.0023 seconds, calculated using the formula T = f 1 ​ where f is the frequency. For a 440 Hz tuning fork, the period reflects the time for one complete vibration. Understanding this concept is crucial in physics when studying sound and waves.
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Answered by facundo3141592 | 2024-10-10