The oxygen saturation of a lake is found by dividing the amount of dissolved oxygen the lake water currently has per liter by the dissolved oxygen capacity per liter of the water, and then converting that number into a percent.
If the lake currently has 7.4 milligrams of dissolved oxygen per liter of water and the dissolved oxygen capacity is 9.4 milligrams per liter, what is the oxygen saturation level of the lake, to the nearest percent?
Answer (2)
To find the oxygen saturation level of the lake, divide the amount of dissolved oxygen in the lake's water per liter ( 7.4 mg/L ) by the water's dissolved **oxygen **capacity per liter (9.4 mg/L) to get the proportion. Multiply this by 100 to convert it into a percentage (78.72%), which rounds to 79% saturation. ;
The oxygen saturation of the lake is calculated to be 79%. This is determined by dividing the dissolved oxygen amount (7.4 mg/L) by its capacity (9.4 mg/L) and converting that ratio into a percentage. Oxygen saturation is essential for the survival of aquatic life.
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