What is the alpha decay of Radon-198?
Answer (3)
86198Rn => 24He + 84194Po
The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.
The alpha decay of **Radon-198 **produces alpha particle and ¹⁹⁴₈₄Po.
What is alpha decay?
Alpha decay is a type of radioactive disintegration in which some **unstable atomic nuclei **spontaneously expel an alpha particle to dissipate excess energy.
Alpha decay of **Radon-198 **is shown as:
¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po
In the above decay from the parent nuclei , daughter nuclei ( ¹⁹⁴₈₄Po ) and alpha particle ( ⁴₂He ) is produced.
Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.
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Radon-198 undergoes alpha decay to produce an alpha particle and Polonium-194. The nuclear equation for this decay is 86 198 R n → 2 4 He + 84 194 P o . This process transforms the unstable Radon-198 into a more stable daughter isotope, Polonium-194.
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