An alarm clock draws 0.5 A of current when connected to a 120-volt circuit. Calculate its resistance.

Given the amount of voltage and the amount of current drawn by the alarm clock , its resistance is 240 ohms.
What is Ohm’s law?
Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance .
It is expressed as;
V = I × R
Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.
Given the data in the question;

Voltage V = 120V

Current I = 0.5A

Resistance R = ?


We substitute our given values into the expression above.
V = I × R
120V = 0.5A × R
R = 120V / 0.5A
R = 240Ω
Therefore, given the amount of voltage and the amount of current drawn by the alarm clock , its resistance is 240 ohms.
Learn more about Ohm's law here: brainly.com/question/2364325
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Answered by nuhulawal20 | 2024-06-15

We need to calculate the resistance of a clock which draws current I=0.5A and is connected to a circuit of V=120V. We can find the resistance of a circuit from Ohm's law: I=U/R where I is the current, U is the voltage and R is the resistance. So lets manipulate Ohm's law to find the resistance: R=U/I. Now we input our numbers: R=120V/0.5A and we get R=240 Ohm. So the resistance is R=240 Ohm.

Answered by W0lf93 | 2024-06-25

The resistance of the alarm clock is 240 ohms, calculated using Ohm's Law. This law relates voltage, current, and resistance. By rearranging the formula R = I U ​ , we found the resistance using the given current and voltage.
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Answered by W0lf93 | 2024-09-26