A 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long, measured along the hill. If there is no friction, how fast will the object be going at the bottom of the hill?

theater=sin^-1(30/80) theater=22 F=400gsin22=150N F=ma 150=400a a=0.375ms^-2 v^2-u^2=2as v^2-0=2x0.375x80 v=7.75ms^-1

Answered by Anonymous | 2024-06-10

The object be going at the bottom of the hill with** velocity** 7.75 m/s.

What is velocity?
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of** time.**
Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no** friction, velocity** with which object be going at the bottom of the hill,
θ =sin^-1(30/80)
θ =22
F = 400 g sin(22) = 150 N
F = ma
150 = 400 a
a = 0.375 m/s²
v² - u²= 2 a s
v² - 0 = 2 x 0.375 x 80
v = 7.75 m/s
The object be going at the bottom of the hill with** velocity** 7.75 m/s.
To learn more about velocity refer the link:
brainly.com/question/18084516
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Answered by eramkhanvt | 2024-06-16

The speed of the 400 kg object at the bottom of the 30 m high hill is approximately 24.2 m/s, calculated using conservation of energy principles. The gravitational potential energy at the top converts into kinetic energy at the bottom. Hence, we used the formulas for potential and kinetic energy to derive the final speed.
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Answered by eramkhanvt | 2025-01-25