Calculate the force between a [tex]$0.006 \, C$[/tex] charge and a [tex]$0.001 \, C$[/tex] charge 4 meters apart.
Answer (3)
F = 4 2 9 ∗ 1 0 9 ∗ 6 ∗ 1 0 − 3 ∗ 1 0 − 3 = 16 54 ∗ 1 0 3 = 3.375 ∗ 1 0 3 N
The required **force **between the two **charges **is approximately 3371.25 N.
What is Coulomb's law?
The **force **between two **point charges **can be calculated using Coulomb's law, which states that:
F = k * (q₁ * q₂) / r²
where F is the force between the charges, k is the Coulomb constant, q₁ and q₂ are the magnitudes of the charges, and r is the distance between them.
In this case, we are given that one charge has a magnitude of 0.006 C and the other has a magnitude of 0.001 C, and they are separated by a distance of 4 meters. So we can substitute these values into Coulomb's law to find the force:
F = (8.99 x 10⁹ ) * [(0.006 ) * (0.001 )] / (4 )²
F = 3371.25 N
Therefore, the **force between **the two **charges **is approximately 3371.25 N.
Learn more about **forces **between **charges **here:
https://brainly.com/question/16858204 #SPJ2
The force between a 0.006 C charge and a 0.001 C charge 4 meters apart is approximately 3371.25 N, calculated using Coulomb's law. This demonstrates the strong electrostatic force present between these two charges. Coulomb's law provides a clear formula for understanding the relationship between charge, distance, and force.
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