the answer to this is solved through stochiometry: the answer is this: 0.0833mol
To find the moles in a 24.5 gram sample of K₂Cr₂O₇, calculate its molar mass (about 294.19 g/mol) and divide the mass by this molar mass. This results in approximately 0.0833 moles of K₂Cr₂O₇. Thus, the answer is 0.0833 moles.
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