What is the current in the circuit if [tex]R_1 = 7 \, \Omega[/tex], [tex]R_2 = 15 \, \Omega[/tex], and the voltage is 220 volts?
Answer (2)
You haven't mentioned whether the resistors are in series or in parallel. It's kind of important, and the answers are different.
If they're in series: The total resistance is (R1 + R2) = (7 + 15) = 22 ohms Current = (voltage) / (total resistance) = (220) / (22) = 10 Amperes
If they're in parallel: The total resistance is (R1 · R2) / (R1 + R2) = (7 · 15) / (7 + 15) = 105/22 ohms Current = voltage / total resistance = 220 · 22 / 105 = 46.1 Amperes.
The poor power supply could probably not deliver 46.1A for very long, so I'm guessing that the resistors are in series, and the current is 10A.
The current in the circuit can be calculated based on the arrangement of resistors. If the resistors are in series, the current is 10 A. If they are in parallel, the current is approximately 46.1 A, but it is likely they are in series based on common scenarios.
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