C a ( O H ) 2
MM = M o l a r ma ss
M M C a ( O H ) 2 = M M C a + 2 ∗ ( M M O + M M H )
M M C a ( O H ) 2 = 40.08 + 2 ∗ ( 16.0 + 1.01 )
M M C a ( O H ) 2 = 40.08 + 2 ∗ ( 17.01 )
M M C a ( O H ) 2 = 40.08 + 34.02
M M C a ( O H ) 2 = 74.1 g / m o l
The mass of one mole of calcium hydroxide Ca(OH) 2 is calculated to be 74.10 grams. This sum includes the contributions from calcium, oxygen, and hydrogen based on their molar masses. In total, you add 40.08 g/mol for Ca, 32.00 g/mol for O, and 2.02 g/mol for H, resulting in 74.10 g/mol.
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