The 6-digit number identified using the clues is 139201, and the result of the mathematical expression [{8 + (12 ÷ 4) × 2}] - 6 is 8.
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Let's work through the problem step-by-step to identify the 6-digit number using the given clues:
The hundreds place digit is the smallest prime number.
The smallest prime number is 2. Therefore, the hundreds place digit is 2.
The ten thousands place digit is thrice its ones digit.
Let's assume the ones digit is x . Then the ten thousands place digit is 3 x .
The ones digit is the predecessor of its hundreds digit.
The hundreds digit, as found in step 1, is 2. Therefore, the ones digit, x , is 1 (since the predecessor of 2 is 1).
The thousands place digit is the largest one-digit number.
The largest one-digit number is 9. So, the thousands place digit is 9.
The lakhs place digit is the successor of the tens place digit.
If the tens place digit is y , the lakhs place digit will be y + 1 .
The tens place digit is the smallest whole number.
The smallest whole number is 0.
Now let's assign the values to the digits:
Lakhs place: Since the tens place is 0, the lakhs place is 0 + 1 = 1 .
Ten thousands place: From step 2, 3 x = 3 × 1 = 3 .
Thousands place: 9 (from step 4)
Hundreds place: 2 (figured out in step 1)
Tens place: 0 (figured out in step 6)
Ones place: 1 (from step 3)
So, the 6-digit number is 139201 .
Next, we solve the expression: [ 8 + ( 12 ÷ 4 ) × 2 ] − 6
First, solve the division: 12 ÷ 4 = 3 .
Next, solve the multiplication: 3 × 2 = 6 .
Add the result to 8: 8 + 6 = 14 .
Finally, subtract 6: 14 − 6 = 8 .
Thus, the answer to the expression is 8 .