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In Mathematics / High School | 2025-07-03

Evaluate:

(a) 17³
(b) (-21/2)²
(c) (-3)⁵
(d) 2⁸
(e) (-3)⁵ × 5²
(f) (-5) × 10⁴
(g) (-6)³ × (-1)²¹
(h) 2⁷ / 8
(i) 3125 / 243
(j) (2/3)² × (-3/5)³ × (-1)¹⁵ × (-1)²⁸ × (1)⁵¹

Asked by fdrlever6934

Answer (2)

(a) To evaluate 1 7 3 :
1 7 3 = 17 × 17 × 17 = 4913
(b) To evaluate ( − 2 21 ​ ) 2 :
( − 2 21 ​ ) 2 = ( 2 21 ​ ) 2 = 4 441 ​ = 110.25
(c) To evaluate ( − 3 ) 5 :
( − 3 ) 5 = ( − 3 ) × ( − 3 ) × ( − 3 ) × ( − 3 ) × ( − 3 ) = − 243
(d) To evaluate 2 8 :
2 8 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256
(e) To evaluate ( − 3 ) 5 × 5 2 :
First, calculate ( − 3 ) 5 :
( − 3 ) 5 = − 243
Then calculate 5 2 :
5 2 = 25
Multiply these results: ( − 3 ) 5 × 5 2 = − 243 × 25 = − 6075
(f) To evaluate ( − 5 ) × 1 0 4 :
( − 5 ) × 1 0 4 = − 5 × 10000 = − 50000
(g) To evaluate ( − 6 ) 3 × ( − 1 ) 21 :
First, calculate ( − 6 ) 3 :
( − 6 ) 3 = ( − 6 ) × ( − 6 ) × ( − 6 ) = − 216
Then evaluate ( − 1 ) 21 :
Since the exponent is odd, ( − 1 ) 21 = − 1 .
Multiply these results: ( − 6 ) 3 × ( − 1 ) 21 = − 216 × − 1 = 216
(h) To evaluate 8 2 7 ​ :
First, find 2 7 :
2 7 = 128
Then divide: 8 128 ​ = 16
(i) To evaluate 243 3125 ​ :
As 3125 and 243 do not share common factors other than 1, we just simplify the fraction as is: 243 3125 ​
(j) To evaluate ( 3 2 ​ ) 2 × ( − 5 3 ​ ) 3 × ( − 1 ) 15 × ( − 1 ) 28 × ( 1 ) 51 :
First, calculate each component: ( 3 2 ​ ) 2 = 9 4 ​ ( − 5 3 ​ ) 3 = 125 − 27 ​ ( − 1 ) 15 = − 1 ( − 1 ) 28 = 1 ( 1 ) 51 = 1
Multiply these results: 9 4 ​ × 125 − 27 ​ × − 1 × 1 × 1 = 9 × 125 4 × ( − 27 ) × − 1 ​ = 1125 108 ​
Simplify 1125 108 ​ if possible, or we can leave it as is. This is the final answer.

Answered by JessicaJessy | 2025-07-06

The evaluations of the expressions yield specific numerical results for each item, such as 1 7 3 = 4913 and ( − 5 ) × 1 0 4 = − 50000 . Each calculation follows standard arithmetic and exponent rules, demonstrating clear steps. The results for each part are systematically derived for clarity and understanding.
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Answered by JessicaJessy | 2025-08-06