How much heat is required to change 15 kg of ice into water at its melting point?
Answer (2)
To convert 15 kg of ice at its melting point to water, approximately 5,010,000 joules of heat energy is required. This is calculated using the latent heat of fusion for ice, which is about 334,000 J/kg. Therefore, the total heat needed is 5,010,000 joules.
;
To calculate the amount of heat required to change 15 kg of ice into water at its melting point, we need to use the concept of latent heat of fusion. The latent heat of fusion is the amount of heat needed to change a substance from solid to liquid at constant temperature and pressure.
For water, the latent heat of fusion is about 334,000 Joules per kilogram (J/kg). This value means that you need 334,000 J of heat to convert 1 kg of ice at 0°C to 1 kg of water at 0°C.
Here's how to calculate the total heat required:
Identify the mass of the ice (m):
The mass given is 15 kg.
Use the latent heat of fusion for ice (L):
The latent heat of fusion for ice is 334 , 000 J/kg .
Apply the formula for heat (Q):
The formula to calculate the heat required is Q = m × L
Substitute the values into the formula:
Q = 15 kg × 334 , 000 J/kg
Calculate the result:
Q = 5 , 010 , 000 J
Therefore, the amount of heat required to melt 15 kg of ice into water at its melting point is 5,010,000 Joules .
