A bicycle is traveling at 15 km/h. How many meters will it cover in 30 seconds?

Convert the speed from km/h to m/s: 15 h km ​ = 15 × 18 5 ​ s m ​ .
Calculate the speed in m/s: 15 × 18 5 ​ = 6 25 ​ s m ​ .
Calculate the distance covered in 30 seconds: Distance = 6 25 ​ s m ​ × 30 s = 125 m .
The bicycle covers 125 ​ meters in 30 seconds.

Explanation

Problem Analysis We are given that a bicycle is traveling at a speed of 15 km/h. We need to find the distance the bicycle covers in 30 seconds, and we need to express the distance in meters. We know that 1 kilometer is equal to 1000 meters.

Converting Units First, we need to convert the speed from km/h to m/s. To do this, we multiply the speed in km/h by 3600 1000 ​ , since there are 1000 meters in a kilometer and 3600 seconds in an hour. So, we have: 15 h km ​ = 15 × 3600 s 1000 m ​ = 15 × 18 5 ​ s m ​

Calculating Speed in m/s Now, we calculate the speed in m/s: 15 × 18 5 ​ = 18 75 ​ = 6 25 ​ s m ​

Calculating Distance Next, we need to find the distance covered in 30 seconds. We use the formula: Distance = Speed × Time So, we have: Distance = 6 25 ​ s m ​ × 30 s = 6 25 × 30 ​ m = 25 × 5 m = 125 m

Final Answer Therefore, the bicycle will cover 125 meters in 30 seconds.


Examples
Understanding how to convert speeds and calculate distances is useful in many real-life scenarios. For example, if you are planning a trip and know the average speed of your car, you can calculate how long it will take to reach your destination. Similarly, if you are tracking the movement of an object, such as a ball thrown in the air, you can use its speed to determine how far it will travel in a given amount of time. These calculations are also crucial in fields like sports, engineering, and physics, where understanding motion and speed is essential.

Answered by GinnyAnswer | 2025-07-03

A bicycle traveling at 15 km/h will cover approximately 125 meters in 30 seconds. This involves converting the speed into meters per second and then applying the distance formula. The detailed calculation shows that this is a straightforward application of unit conversion and basic motion principles.
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Answered by Anonymous | 2025-07-04