An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?
Answer (2)
Assume the equation of the given line is y = 2 and point P lies on this line.
Check if the y-coordinates of the given points are equal to 2.
Points a ( − 4 , 2 ) , c ( − 2 , 2 ) , and d ( 4 , 2 ) satisfy the equation y = 2 .
Therefore, the points that lie on the line are a, c, and d. a , c , d
Explanation
Problem Analysis The problem asks us to identify three points that lie on a line that passes through a point P and is parallel to a given line. Unfortunately, the coordinates of point P and the equation of the given line are not provided. Therefore, I will make an assumption to illustrate the solution process.
Assumption Let's assume the equation of the given line is y = 2 . This means the line is horizontal. Also, let's assume that point P lies on this line. Then the line we are looking for is also y = 2 , since it is parallel to the given line and passes through point P.
Checking the points Now, we check which of the given points satisfy the equation y = 2 :
a ( − 4 , 2 ) : The y-coordinate is 2, so this point lies on the line. b ( − 1 , 3 ) : The y-coordinate is 3, so this point does not lie on the line. c ( − 2 , 2 ) : The y-coordinate is 2, so this point lies on the line. d ( 4 , 2 ) : The y-coordinate is 2, so this point lies on the line.
Conclusion Based on our assumption, points a ( − 4 , 2 ) , c ( − 2 , 2 ) , and d ( 4 , 2 ) satisfy the equation y = 2 . Therefore, these three points lie on the line.
Examples
In architecture, determining parallel lines is crucial for designing structures with consistent heights or aligning features. For example, when designing a building facade, architects use parallel lines to ensure that windows on different floors are aligned, creating a visually appealing and structurally sound design. Similarly, in urban planning, parallel streets are often used to create organized and efficient city layouts.
About 2.81 billion billion electrons flow through the device when a current of 15.0 A runs for 30 seconds. This is calculated by finding the total charge and dividing it by the charge of a single electron. The formulae used are based on the relationships between current, charge, and the number of electrons.
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