What is the final chemical equation from the following intermediate chemical equations?
[tex]
\begin{array}{l}
P_4 O_6(s) \rightarrow P_4(s)+3 O_2(g) \
P_4(s)+5 O_2(g) \rightarrow P_4 O_{10}(s)
\end{array}
[/tex]
Answer (2)
The final chemical equation derived from the given intermediate reactions is P 4 O 6 ( s ) + 2 O 2 ( g ) → P 4 O 10 ( s ) . This equation represents the reaction between phosphorus trioxide and oxygen to produce phosphorus pentoxide. The process involves combining and simplifying the intermediate equations to eliminate intermediates and obtain a balanced equation.
;
Add equations 1 and 2 to eliminate P 4 ( s ) .
Simplify the resulting equation: P 4 O 6 ( s ) + 2 O 2 ( g ) → P 4 O 10 ( s ) .
Compare the result with the given equations and confirm that it matches equation 3.
The final chemical equation is: P 4 O 6 ( s ) + 2 O 2 ( g ) → P 4 O 10 ( s )
Explanation
Problem Analysis We are given a set of intermediate chemical equations and asked to find the final chemical equation. The strategy here is to manipulate the given equations to eliminate intermediate species and arrive at the overall balanced equation.
Listing Given Equations We are given the following equations:
P 4 O 6 ( s ) i g h t ha r p oo n u p P 4 ( s ) + 3 O 2 ( g )
P 4 ( s ) + 5 O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
P 4 O 6 ( s ) + 2 O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
P 4 O 6 ( s ) + 8 O 2 ( g ) i g h t ha r p oo n u p 2 P 4 ( s ) + P 4 O 10 ( s )
P 4 O 6 ( s ) + 15 O 2 ( g ) i g h t ha r p oo n u p P 4 ( s ) + P 4 O 10 ( s )
P 4 O 6 ( s ) + ( 5/3 ) O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
Adding Equations 1 and 2 We can add equations 1 and 2 to eliminate P 4 ( s ) .
Adding equations 1 and 2: P 4 O 6 ( s ) + P 4 ( s ) + 5 O 2 ( g ) i g h t ha r p oo n u p P 4 ( s ) + 3 O 2 ( g ) + P 4 O 10 ( s )
Simplifying the Result Simplifying the equation by canceling out P 4 ( s ) from both sides, we get: P 4 O 6 ( s ) + 2 O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
Comparing with Given Equations Comparing this result with the given equations, we see that equation 3 is the same as the result of adding equations 1 and 2.
Equation 3: P 4 O 6 ( s ) + 2 O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
Final Chemical Equation Therefore, the final chemical equation is: P 4 O 6 ( s ) + 2 O 2 ( g ) i g h t ha r p oo n u p P 4 O 10 ( s )
Examples
In chemistry, balancing chemical equations is crucial for understanding stoichiometry, which helps in calculating the amounts of reactants and products involved in a chemical reaction. For instance, in industrial processes, knowing the exact amount of oxygen needed to react with a certain amount of phosphorus oxide ( P 4 O 6 ) to produce phosphorus pentoxide ( P 4 O 10 ) is essential for optimizing the reaction yield and minimizing waste. This ensures efficient production and reduces environmental impact by preventing the release of unreacted materials.
