How many atoms are present in 7.0 moles of Ca?
Answer (2)
Multiply the number of moles of Calcium by Avogadro's number.
Perform the calculation: 7.0 \t × 6.022 × 1 0 23 .
The result is 4.2154 × 1 0 24 atoms.
Therefore, the number of atoms present in 7.0 moles of Ca is 4.2154 × 1 0 24 .
Explanation
Understanding the Problem We are asked to find the number of atoms present in 7.0 moles of Calcium (Ca). To do this, we will use Avogadro's number, which is the number of atoms, molecules, or ions in one mole of a substance. Avogadro's number is approximately 6.022 \t × 1 0 23 atoms/mole.
Calculations To find the number of atoms in 7.0 moles of Ca, we multiply the number of moles by Avogadro's number:
Number of atoms = (moles of Ca) × Avogadro's number
Number of atoms = 7.0 × 6.022 \t × 1 0 23
Final Answer Performing the multiplication:
Number of atoms = 7.0 × 6.022 \t × 1 0 23 = 4.2154 \t × 1 0 24 atoms
Examples
Understanding the number of atoms in a given amount of substance is crucial in various fields. For example, in chemistry, when you're mixing reactants for a chemical reaction, knowing the number of atoms helps you determine the precise amount of each substance needed to achieve the desired reaction. In material science, it helps in designing new materials with specific properties by controlling the arrangement and quantity of atoms. In cooking, if you were to consider the 'chemical reaction' of baking, understanding the molar quantities helps ensure proper ratios of ingredients for the perfect cake!
In 7.0 moles of Calcium (Ca), there are approximately 4.2154 × 1 0 24 atoms. This is calculated by multiplying the number of moles by Avogadro's number. Avogadro's number is approximately 6.022 × 1 0 23 atoms/mole.
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