Use [tex]$pH=-\log [H+]$[/tex] to find [tex]$[H+]$[/tex]
Milk has a pH of 6.6. What is the hydrogen concentration [tex]$[H+]$[/tex] (in moles per liter) of milk?
A. [tex]$-\log 6.6$[/tex]
B. [tex]$log 6.6$[/tex]
C. [tex]$10^{-6.6}$[/tex]
D. [tex]$10^{6.6}$[/tex]
Answer (2)
Substitute the given pH value into the formula p H = − lo g [ H + ] .
Solve the equation 6.6 = − lo g [ H + ] for [ H + ] .
Multiply both sides of the equation by -1: − 6.6 = lo g [ H + ] .
Take the antilog (base 10) of both sides to isolate [ H + ] : [ H + ] = 1 0 − 6.6 .
The hydrogen concentration [ H + ] is 1 0 − 6.6 moles per liter.
Explanation
Understanding the Problem We are given the formula p H = − lo g [ H + ] and the pH of milk, which is 6.6. We need to find the hydrogen concentration [ H + ] .
Substituting the pH Value Substitute the given pH value into the formula: 6.6 = − lo g [ H + ]
Multiplying by -1 To solve for [ H + ] , we first multiply both sides of the equation by -1: − 6.6 = lo g [ H + ]
Taking the Antilog Now, we take the antilog (base 10) of both sides to isolate [ H + ] : [ H + ] = 1 0 − 6.6
Calculating the Concentration Calculating 1 0 − 6.6 , we find that the hydrogen concentration is approximately 2.51 × 1 0 − 7 moles per liter.
Final Answer Therefore, the hydrogen concentration [ H + ] of milk is 1 0 − 6.6 moles per liter.
Examples
Understanding pH and hydrogen concentration is crucial in many real-world applications. For instance, in agriculture, knowing the pH of the soil helps farmers determine the suitability of the soil for different crops. In medicine, maintaining the correct pH balance in the body is essential for various biological processes. In environmental science, monitoring the pH of water bodies helps assess water quality and the impact of pollutants. The concept of pH and its calculation are fundamental in chemistry and biology, providing a quantitative measure of acidity or alkalinity.
The hydrogen concentration [ H + ] of milk with a pH of 6.6 is 1 0 − 6.6 moles per liter. The correct answer choice from the options provided is C. 1 0 − 6.6 .
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