Fill in the gaps to balance the equation.
Use the smallest set of whole numbers to balance the equation and include coefficients of "1" when appropriate.
[tex]$\square$ LiI + $\square$ H _2 SO _4 \rightarrow $\square$ Li _2 SO _4+ $\square$ HI[/tex]
Complete the table to determine how many atoms of each element are present in the reactants and products.
| Element | Reactant | Products |
| :------ | :------- | :------- |
| Li | $\square$ | $\square$ |
| I | $\square$ | $\square$ |
| H | $\square$ | $\square$ |
| S | $\square$ | $\square$ |
| O | $\square$ | $\square$
Answer (2)
Balance the Lithium (Li) atoms by placing a coefficient of 2 in front of L i I .
Balance the Iodine (I) atoms by placing a coefficient of 2 in front of H I .
Verify that Hydrogen (H), Sulfur (S), and Oxygen (O) atoms are already balanced.
The balanced equation is 2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I , and the table is completed with corresponding atom counts. 2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I
Explanation
Analyzing the Chemical Equation We're going to balance the chemical equation step-by-step, making sure we have the same number of each type of atom on both sides. This is like making sure a seesaw is balanced with equal weight on each side!
Balancing Lithium (Li) Let's start with the unbalanced equation:
L i I + H 2 S O 4 → L i 2 S O 4 + H I
We'll balance Lithium (Li) first. We have 1 Li on the left and 2 on the right. So, we put a '2' in front of L i I on the left:
2 L i I + H 2 S O 4 → L i 2 S O 4 + H I
Balancing Iodine (I) Now, let's balance Iodine (I). We have 2 I on the left and 1 on the right. So, we put a '2' in front of H I on the right:
2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I
Checking Hydrogen (H) Next, let's check Hydrogen (H). We have 2 H on the left (in H 2 S O 4 ) and 2 H on the right (in 2 H I ). So, Hydrogen is already balanced!
Checking Sulfur (S) Sulfur (S) is next. We have 1 S on the left (in H 2 S O 4 ) and 1 S on the right (in L i 2 S O 4 ). So, Sulfur is balanced!
Checking Oxygen (O) Finally, let's check Oxygen (O). We have 4 O on the left (in H 2 S O 4 ) and 4 O on the right (in L i 2 S O 4 ). So, Oxygen is also balanced!
Balanced Equation So, the balanced equation is:
2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I
Completing the Table Now, let's complete the table:
Element
Reactant
Products
Li
2
2
I
2
2
H
2
2
S
1
1
O
4
4
Final Answer The balanced equation is 2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I , and the table is filled with the number of atoms of each element on both sides.
Examples
Balancing chemical equations is like cooking! Imagine you're baking a cake. You need the right amount of each ingredient (flour, sugar, eggs) to get the perfect cake. If you have too much of one ingredient or not enough of another, the cake won't turn out right. Similarly, in chemistry, you need the right number of atoms of each element to make a chemical reaction work correctly. Balancing equations ensures that matter is conserved, just like having the right recipe ensures a delicious cake!
The balanced equation is 2 L i I + H 2 S O 4 → L i 2 S O 4 + 2 H I . The atom count for each element in the reactants and products confirms this balance. The completed table reflects 2 lithiums, 2 iodines, 2 hydrogens, 1 sulfur, and 4 oxygens on both sides.
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