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In Physics / College | 2025-07-07

An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?

Asked by goldgatchalian53

Answer (2)

The device delivers a current of 15.0 A for 30 seconds, resulting in a total charge of 450 C. This charge corresponds to approximately 2.81 x 10^21 electrons flowing through the device. The calculations utilize the formulas for charge and the charge of a single electron.
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Answered by Anonymous | 2025-07-07

Calculate the values of the given expressions.
Match the calculated values to the letters in the tables.
Form the message using the matched letters.
The partial message formed is S I LL MOEEO ​ .

Explanation

Calculate the values of the expressions First, we need to calculate the values of the given expressions:

4 11 ​ × 7 6 ​ = 4 × 7 11 × 6 ​ = 28 66 ​ = 14 33 ​ ≈ 2.357

5 3 ​ × 2 21 ​ = 5 × 2 3 × 21 ​ = 10 63 ​ = 6.3

7 5 ​ × 7 14 ​ = 7 × 7 5 × 14 ​ = 49 70 ​ = 7 10 ​ ≈ 1.429

5 3 ​ × 125 = 5 3 × 125 ​ = 5 375 ​ = 75

4 3 ​ × 3 4 ​ = 4 × 3 3 × 4 ​ = 12 12 ​ = 1

5 12 ​ × 4 31 ​ = 5 × 4 12 × 31 ​ = 20 372 ​ = 5 93 ​ = 18.6

3 22 ​ × 4 3 ​ = 3 × 4 22 × 3 ​ = 12 66 ​ = 2 11 ​ = 5.5

3 5 4 ​ × 12 5 ​ = 5 19 ​ × 12 5 ​ = 5 × 12 19 × 5 ​ = 60 95 ​ = 12 19 ​ ≈ 1.583

6 5 ​ × 2 = 6 5 × 2 ​ = 6 10 ​ = 3 5 ​ ≈ 1.667

4 1 ​ × 76 = 4 76 ​ = 19

42 3 2 ​ × 51 4 1 ​ = 3 128 ​ × 4 205 ​ = 3 × 4 128 × 205 ​ = 12 26240 ​ = 3 6560 ​ ≈ 2186.667

3 2 ​ × 60 = 3 2 × 60 ​ = 3 120 ​ = 40

43 4 3 ​ × 5 4 ​ = 4 175 ​ × 5 4 ​ = 4 × 5 175 × 4 ​ = 20 700 ​ = 35

33 4 3 ​ × 57 9 7 ​ = 4 135 ​ × 9 520 ​ = 4 × 9 135 × 520 ​ = 36 70200 ​ = 1950

8 3 ​ × 72 = 8 3 × 72 ​ = 8 216 ​ = 27

$62\frac{2}{5} \times \frac{21}{2} = \frac{312}{5} \times \frac{21}{2} = \frac{312 \times 21}{5 \times 2} = \frac{6552}{10} = 655.2

Match the values to letters Now, we match the calculated values to the letters in the tables:

2.357 -> S

6.3 -> None

1.429 -> I

75 -> L

1 -> L

18.6 -> None

5.5 -> None

1.583 -> M

1.667 -> None

19 -> O

2186.667 -> None

40 -> E

35 -> E

1950 -> None

27 -> O

655.2 -> None


Since some values don't directly correspond to a letter, we will look for approximate matches or consider if there's a typo in the provided tables or calculations. Let's re-examine the tables and calculations.
After re-examining, it seems there are no direct matches for 6.3, 18.6, 5.5, 1.667, 2186.667, 1950, and 655.2. This suggests that either the message is incomplete, or there might be a different interpretation of the problem. Given the available information, we can only form a partial message.

Form the message Based on the calculations and the letter mappings, the partial message we can form is:

S I L L M O E E O
Since we cannot form a complete meaningful message with the given data, we must acknowledge that the problem might be designed to be unsolvable with the provided tables, or there might be missing information.
Examples
This type of problem, where you decode a message by performing calculations and matching the results to a code, is similar to how encryption works. In real life, more complex mathematical operations are used to encrypt sensitive information, such as passwords or financial data, to keep it secure during transmission over the internet. By solving this problem, you're practicing the basic principles behind cryptography, which is a crucial field in cybersecurity.

Answered by GinnyAnswer | 2025-07-07