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In Mathematics / College | 2025-07-07

Evaluate. (Assume $x>0$.) Check by differentiating.

$\int 5 x \ln \sqrt[4]{x} d x$

$\int 5 x \ln \sqrt[4]{x} d x=$

Asked by tahj9k

Answer (1)

Simplify the integrand using the logarithm property: ln 4 x ​ = 4 1 ​ ln x .
Apply integration by parts to evaluate ∫ x ln x d x , choosing u = ln x and d v = x d x .
Substitute the result back into the original expression and simplify.
The final result of the integration is: 8 5 ​ x 2 ln x − 16 5 ​ x 2 + C ​ .

Explanation

Problem Analysis We are asked to evaluate the indefinite integral ∫ 5 x ln 4 x ​ d x , assuming that 0"> x > 0 , and to check the result by differentiating.

Simplifying the Integrand First, we simplify the integrand using the logarithm property ln a b = b ln a . In our case, 4 x ​ = x 4 1 ​ , so ln 4 x ​ = ln x 4 1 ​ = 4 1 ​ ln x . Therefore, the integral becomes ∫ 5 x ln 4 x ​ d x = ∫ 5 x ⋅ 4 1 ​ ln x d x = 4 5 ​ ∫ x ln x d x

Applying Integration by Parts Next, we evaluate the integral ∫ x ln x d x using integration by parts. The formula for integration by parts is ∫ u d v = uv − ∫ v d u . We choose u = ln x and d v = x d x . Then, we find d u = x 1 ​ d x and v = 2 1 ​ x 2 .

Evaluating the Integral Substituting these into the integration by parts formula, we get ∫ x ln x d x = ( ln x ) ( 2 1 ​ x 2 ) − ∫ 2 1 ​ x 2 ⋅ x 1 ​ d x = 2 1 ​ x 2 ln x − 2 1 ​ ∫ x d x = 2 1 ​ x 2 ln x − 2 1 ​ ⋅ 2 1 ​ x 2 + C = 2 1 ​ x 2 ln x − 4 1 ​ x 2 + C

Substituting Back Now, we substitute this result back into the original integral expression: 4 5 ​ ∫ x ln x d x = 4 5 ​ ( 2 1 ​ x 2 ln x − 4 1 ​ x 2 ) + C = 8 5 ​ x 2 ln x − 16 5 ​ x 2 + C

Final Result Thus, the indefinite integral is ∫ 5 x ln 4 x ​ d x = 8 5 ​ x 2 ln x − 16 5 ​ x 2 + C

Checking by Differentiating To check our result, we differentiate it with respect to x :
d x d ​ ( 8 5 ​ x 2 ln x − 16 5 ​ x 2 + C ) = 8 5 ​ ( 2 x ln x + x 2 ⋅ x 1 ​ ) − 16 5 ​ ( 2 x ) = 4 5 ​ x ln x + 8 5 ​ x − 8 5 ​ x = 4 5 ​ x ln x = 5 x ⋅ 4 1 ​ ln x = 5 x ln 4 x ​

Verification The derivative of our result matches the original integrand, so our integration is correct.


Examples
Imagine you're calculating the total work done by a motor where the force applied changes logarithmically with displacement. This integral helps determine the accumulated work, crucial for designing efficient mechanical systems and predicting energy consumption in engineering applications.

Answered by GinnyAnswer | 2025-07-07